What I want is to have a multiple-line text input, and to be able to count the number of lower-case letters, upper-case letters, periods, commas, spaces, line-breaks, and other characters in the input.
I am trying to use just one string with getline for inputs in a while loop with a running count for each punctuation category.
I just don't know how to actually figure out how many of each character type there are in each line. Given a string, how do I count the number of each type?
Here is my code so far (obviously incomplete):
#include <iostream>
#include <iomanip>
#include <cstdlib>
#include <cmath>
#include <string>
using namespace std;
int main(){
cout << "This program takes any number of sentences as inputs. " << endl;
cout << "It will count the number of lower-case letters and upper-case letters. " << endl;
cout << "It will also count the number of periods, exclamation marks, spaces, end-lines, etc. " << endl;
cout << " " << endl;
cout << "Please type your text, pressing enter whenever you wish to end a line. " << endl;
cout << "Use the EOF key (CTRL + Z on Windows) when you are finished. " << endl;
string InputString; // This is the string that will be used iteratively, for each line.
int NumberOfLowerCase = 0;
int NumberOfUpperCase = 0;
int NumberOfSpaces = 0; // spaces
int NumberOfTabs = 0; // tabs
int NumberOfPeriods = 0; // periods
int NumberOfCommas = 0; // commas
int NumberOfOtherChars = 0; // other characters
int NumberOfEnters = 0; // end of line, will be incremented each loop
do {
getline(cin, InputString); // input
cout << InputString << endl; // filler just to test the input
NumberOfLowerCase = NumberOfLowerCase + 0 // I don't know what I should be adding
// (obviously not zero, that's just a filler)
} while (!cin.eof() && cin.good());
system("pause");
return 0;
}
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